If sin a = (3/14) find cos a and tan (a)

sin(a) = 3/14

We need to determine
sin(a) and tan(a).

We will use the trigonometric properties to find
cos(a) and tan(a).

We know that: sin^2 x + cos^2 a =
1

 Let us substitute with sin(1) =
3/14.

==> (3/14)^2 + cos^2 a =
1

--< cos^2 a = 1-
(9/196)

==> cos^2 a = 187/
196

==> cos(a) = sqrt(187) /
14

Now let us calculate
tan(a).

From trigonometric properties, we know that tan(a) =
sin(a)/cos(a).

==> tan(a) = (3/14) / ( sqrt187/
14)

                  =
3/sqrt187

==> tan(a) = 3/
sqrt(187)