What is the easiest way to integrate csc^2x/cotx dx

Here cot x is in the denominator. But it can be seen that the
numerator has (csc x)^2. We know that the derivative of cot x is -(csc
x)

The integral can be solved in the easiest way by
substitution.

Int[ (csc x)^2 / cot x
dx]

let y = cot x

-dy = csc x
dx

=> Int [ (-1/y) dy]

=>
-log|y| + C

substitute y = cot
x

=> - log |cot x| +
C

The required integral is -log |cot x| +
C