If a two digit number increases by 54 when the digits are
reversed, what is the number.
Let the 2 digits in order be
x and y.
Then the value of the number =
10x+y.
When the digits are reversed , the digits in order
are y and x.
So the valuse of the number is
10y+x.
Since 10y+x -(10x+y) =
54,
9y -9x = 54.
Or y-x=
6.
Therefore y = x+6.
So the
digits in the solution are when x= 1, y = 1+6 = 7.
When
x=2, y = 2+6 = 8.
When x= 3, y = 3+6 = 6 =
9.
Therefore there are 3 solutions : 17 ; 28 and 39
which, when reversed, become 71 ; 82 and and 93 each increase by 54 after reversing
the digits.
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