The standard expression for a linear function
is:
f(x) = ax + b, where
a>0
We'll impose the constraint from enunciation and
we'll get:
f(f(x)) = a*f(x) +
b
We'll substitute f(x) by
ax+b
f(f(x)) = a(ax+b) +
b
We'll remove the brackets and we'll
have:
f(f(x)) = a^2*x + ab + b
(1)
But f(f(x)) = 4x + 3
(2)
We'll put (1) = (2):
a^2*x
+ ab + b = 4x + 3
For te expressions to be equal the
correspondent coefficients have to be equal:
a^2 =
4
ab + b = 3 => b(a+1) = 3
(3)
Because a>0 => a =
sqrt4
a =
2
We'll substitute a in
(3):
b(a+1) = 3
b(2+1) =
3
3b = 3
We'll divide by
3:
b =
1
The linear function f(x) =
2x + 1.
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