Let the numbers be x and
y.
Given that the product of the of the numbers is
1296.
x*y = 1296
==> y=
1296/ x
Let the sum of the numbers be f(x) = x+
y.
We will wrtie f(x) as a function of
x.
==> f(x) = x + (
1296/x)
==> f(x) = (x^2 +
1296)/x
Now we need to find the extreme value for
f(x).
Let us find the first
derivative.
==> f'(x) = ( 2x*x - x^2+
1296))/(x^2)
= ( 2x^2 - x^2 + 1296) /
x^2
= ( x^2 -
1296)/x^2
==> f'(x) = (x^2 -
1296)/x^2
==> (x^2 - 1296 =
0
==> x^2 =
1296
==> x= 36
Then the
function has extreme value at x= 36.
==> y=
36.
Then, the maximum sum of the two numbers
is 36+ 36 = 72.
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