We conclude that the function we have to determine is a
linear function, because the result of the sum of the functions is a linear function 4x
- 1.
We'll substitute x by 1-x in the given
relation.
2f(1-x) + 3f(x) = 4(1-x) -
1
We'll remove the brackets form the right
side:
2f(1-x) + 3f(x) = 4 - 4x -
1
We'll combine like
terms:
2f(1-x) + 3f(x) = 3 - 4x
(1)
2*f(x) + 3*f(1-x) = 4x - 1
(2)
We'll eliminate the unknown f(1-x). For this reason,
we'll multiply (1) by 3 and (2) by -2:
6f(1-x) + 9f(x) = 9
- 12x (3)
-6f(1-x) - 4f(x) = -8x + 2
(4)
We'll add (3) +
(4):
6f(1-x) + 9f(x) - 6f(1-x) - 4f(x) = 9 - 12x - 8x +
2
We'll eliminate and combine like
terms:
5f(x) = -20x + 11
We'll
divide by 5:
The function
is:
f(x) = -4x +
11/5
Another method of solving the problem
is to consider the linear function:
f(x) = ax +
b
f(1-x) = a(1-x) + b
f(1-x) =
a - ax + b
We'll re-write the expression 2*f(x) + 3*f(1-x)
= 4x - 1
2ax + 2b - 3ax + 3a + 3b = 4x -
1
We'll combine like
terms:
-ax + 3a + 5b = 4x -
1
The expressions from both sides are equal if the
correspondent coefficients are equal.
-a =
4
a =
-4
3a + 5b =
-1
3*(-4) + 5b = -1
-12 + 5b =
-1
5b = 11
b =
11/5
f(x) = -4x +
11/5
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