Four consecutive odd integers have the sum of 64. Which are the integers .

We'll write the first odd integer as
x.

The second consecutive odd integer is x +
2.

The third consecutive odd integer is x +
4.

The fourth consecutive odd integer is x +
6.

The sum of the integers is
64:

x + (x+2) + (x+4) + (x+6) =
64

Now, we'll remove the brackets and we'll combine like
terms:

4x + 12 = 64

We'll
subtract 12 both sides:

4x = 64 -
12

4x = 52

We'll divide by
4:

x = 13

The first odd
integer is x = 13.

The second consecutive odd integer is x
+ 2 = 13 + 2 = 15.

Th third consecutive odd integer is x +
4 = 13 + 4 = 17

The fourth consecutive odd integer is x + 6
= 13 + 6 = 19

The 4 consecutive odd integers
are {13 ; 15 ; 17 ; 19}.