To find the linear functions of f and g if x-2 = 2f(x-1)
+3g(x+1).
Let us assume that x-2 is a function of (x-1)
and (x+1).
So 2k (x-1) +3l(x+1) =
(x-2).
Equating the coeffficients of x and constanrs on
both sides, we get:
(2k+3l)x = x,
Or
2k+3l =
1........(1).
-2k+3l =
-2.........(2).
(1)+(2) gives: 6l = -1, Or l =
-1/6.
(1)-(2) gives: 4k = 3, Or k =
3/4.
Therefore f(x) = (3x/4) and g(x) =
-(x/6)
Verification: 2f(x-1) + 3g(x+1) = 6/4(x-1) -3/6(x+1)
= x-2.
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