What is the area of the rectangle whose length is 3 times the width and the perimeter is 24.

To find the area of the rectangle, first we need to
determine the length and the width.

Let the length be L and
the width be W.

Given that the length = 3 times the
width.

Then we will write:

L =
3W.............(1)

Also, given that the perimeter (P) =
24

==> 2L +2W =
24

Divide by 2:

==> L +
W = 12...........(2)

Now let us substitute (1) in
(2).

==> 3W + W =
12

==> 4*W = 12

Now we
will divide by 4.

==> W = 12/4 =
3

Then, W = 3 and L = 3*3 =
9

Then the length of the rectangle = 9, and the width =
3

Now we will calculate the
area.

Area = L*W = 3* 9 =
27

Then, the area of the rectangle = 27
square units.