Yes, it is possible for x = 0. But let's prove
it!
We'll have to solve the equation x - sin x =
0.
The equation is a transcedental one, so we'll have to
differentiate the function f.
Before differentiating, we'll
check if the function is continuous. Because f(x) is formed by elementary functions as
the linear one, x , and the trigonometric function, sin x, f(x) is a continuous
function.
We'll differentiate
f(x).
df/dx =
1-cosx
We notice that f(x) is a monotone increasing
function.
( -1<cosx<1), so the difference 1
-cos x>0 =>f(x)>0, so f(x) is an
injection.
We can also do a very simple
calculus:
f(0)=0-sin0=0-0=0.
Because
f(x) is an one-to-one, x=0 is the only solution for the equation
x-sinx=0.
So, yes, x = sin x, for x =
0.
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