Solve the following system of linear equations. Present your solution as an ordered pair (x,y) 3x + 4y = 11 x - 2y = 7

solve the following
system:

3x+4y=11

x-2y=7

Step
1.)

Solve any one of the
equations for one variable in terms of the other. By
solving 3x=4y=7 for x, we
find

3x=-4y+11, devide this by
three so that it
become

x=-4y+11/3

Step
2.)
Next, we back-substitute into the equation x-2y=7 as
follows

(-4y+11)/3-2y=7

(-4y+11-6y)/3=7......cross
multiply

-4y+11-6y=7(3)

-4y+11-6y=21

-4y-6y=21-11

-10y=10.........divide
this by
10

y=-1

step
3.)

Now, we have
to find the x-coordinate of the point of intersection of the two lines.
Back-substituting into the equation 3x+4y=11
, we
get

3x+4(-1)=11

3x-4=11

3x=11+4.....divide
this by
three

x=15/3

x=5

Therefore,
the solution to the linear system of equations or the point of intersection
of
the two lines is (5,-1).