What are a and b if their product is 240 and b is 4 less than twice a.

Given that the product of a and b is
240

Then we will rewrite:

a * b = 240
.............(1)

Now we know that b is 4 less than twice
a.

Then we rewrite:

b= 2a -
4..............(2)

Now we will solve the system by substituting (2)
into (1).

==> a* (2a-4) =
240

==> 2a^2 - 4a =
240

==> 2a^2 - 4a - 240 = 0

Now
we will divide by 2.

==> a^2 - 2a - 120 =
0

==> Now we will
factor:

==> (a-12)(a+10) =
0

==> a1 = 12 ==> b1 =
20

==> a2= -10 ==> b2=
-24

Then we have two
solutions:

The solution are : ( 12, 20) and (-10, -24)