What is the perimeter of the rectangle whose width is two third the length and the area is 96

Let the length of the rectangle be L and the width be
W.

Given that the width is 2/3 of the
length.

Then, we will write:

W
= (2/3)*L................(1)

Also, given that the area of
the rectangle is 96.

Then,

A =
w*L = 96..............(2)

Now we will substitute (1) into
(2).

==> W*L =
96

==> (2/3)*L * L =
96

==> (2/3)*L^2 =
96

Now we will multiply by
3/2.

==> L^2 =
96*3/2

==> L^2 =
144

Now we will take the root of both
sides;

==> L = 12
.

==> W = (2/3)L = (2/3)*12 =
8

==> W = 8.

Now we
will calculate the perimeter;

==> P = 2L + 2W = 2*12
+ 2*8 = 24 + 16 = 40.

Then, the perimeter of
the rectangle is 40 units.