a 300ml sample of gas at 10degree Celsius is warmed to 60 degree Celsius at a constant pressure. calculate the final volume.remember that the...

This is an application of Charles's Law which relates
changes in volume to changes in temperature. Conceptually what it says is that when you
increase the temperature of a gas, the volume will also increase and when you decrease
the gas temperature the volume will also decrease.

The
formula is:  V1/T1 = V2/T2

where V1 is the initial volume
in liters or mL

T1 is the initial temperature in degrees
Kelvin (K)

V2 is the final temperature in liters or
mL.

T2 is the final temperature in degrees
Kelvin.

To convert degrees celsius to degrees Kelvin use
the formula:

K = 273.15 + degrees
C

This must be done because sometimes you are dividing by
the value of the temperature and if you used degrees celsius you could end up trying to
divide by zero!

In your problem, to solve, first identify
the variables:

V1 = 300 mL

T1
= 10 degrees celsius or 283.15 K

V2 =
?

T2 = 60 degrees celsius or 333.15
K

Substituting into the equation you
get:

300/283.15 =
V2/333.15

Multiply both sides by 333.15 to solve for V2 and
you get:

(300 x 333.15)/283.15 =
V2

V2 = 352.98 mL

To analyze
similar problems look for key terms:

from usually implies
an initial value

to usually implies a final
value

heating usually means going from an initial T to a
final T

cooling usually means going from a final T  to an
initial T.