solve for x values: x^2 - 5x + 6 > 0

x^2 - 5x + 6 > 0

Let
us factor:

==> (x-2)(x-3) >
0

Now we have 2 cases:

case(1)
:

x-2  > 0      and  (x-3) >
0

==> x>2     and  x >
3

==> x = (2, inf) intersects (3, inf) = ( 3,
inf)

Case(2):

x-2
< 0    and   x-3 < 0

x < 2      and  
x < 3

==> x = (-inf, 2)  and (-inf, 3) =
(-inf, 2)

==> x = ( -inf, 2) U ( 3,
inf)

OR

   x = R - [2, 3]