The indefinite integral
is:
Int f(x)dx = Int (1/x +
6x^2)dx
We'll use the additive property of
integral:
Int (1/x + 6x^2)dx = Int (1/x)dx + Int
(6x^2)dx
Int (1/x)dx = ln |x| +
C
Int (6x^2)dx = 6 Int x^2dx
6
Int x^2dx = 6x^3/3 + C
6 Int x^2dx = 2x^3 +
C
Int (1/x + 6x^2)dx = ln |x| + 2x^3 +
C
Note: We've considered the absolute value of x, because
it is not assigned an interval of values for x.
No comments:
Post a Comment