if f(x) = 2x^5 - 3x^3 + 5x then find f''(1)

f(x) = 2x^5 - 3x^3 +
5x   

First we will determine first derivative
f'(x)

f'(x) = 2*5x^4 - 3*3x^2 +
5*1

       = 10x^4 - 9x^2 +
5

Now we will determine f''(x) by differentiate
f'(x).

f''(x) = 10^4x^3 -
9*2x

        = 40x^3 - 
18x

Now we will substiute with
x=1

==> f''(1) = 40*1 - 18*1 =
22

==> f''(1) =
22