The polinomial f(x) divided x-3 results in a quotient of x^2+3x-5 and reminder of two. Find f(3).

Given that the quotient of dividing f(x) by (x-3) , the results
will be x^2 + 3x -5  and remainder of 2:

Then f(x) is a product of
two functions, including (x-3), plus two.

==> f(x) =
(x-3)*R(x) + 2

Let us write :

f(x) /
(x-3) = (x^+ 3x -5) + 2

We will multiply by
(x-3).

==> f(x) = (x-3)(x^2 +3x -5) +
2

Now to find f(3) we will substitute with x= 3
:

f(3) = (3-3)( 3^2 + 3&3 -5) +
2

==> f(3) = 0 + 2 = 2

Then, we
know that:

f(3) =
2