Find the solution of the exponential equation 2^(1-x)=19 in terms of logarithms or correct the four decimal places.

2^(1-x) = 19

==> To solve
the equality, we will us the logarithm form.

==> First. let
us apply the logarithm to both sides:

==> log 2^(1-x) = log
19

Now we know from logarithm properties
that:

log a^b = b *log a

==> log
2^(1-x) = log 19

==> (1-x)*log 2 = log
19

Now we will divide by log
2

==> (1-x) = log 19/ log
2

==> -x = log 19/ log 2  -
1

Now multiply by -1.

==>  x = 1
- log19/log2

==> x = 1 -
4,2479

            =
-3,2479

Then, the answer is x =
-3,2479.