Let x be one side of the
   square.
We'll write the formula for the area of the
   square:
A = x^2
We'll write the formula
   for the perimeter of the square:
P =
   4x
Now, we'll write mathematically the condition imposed by
   enunciation:
x^2 = 4x + 45 (area is equal to the perimeter plus
   45)
We'll subtract both sides 4x +
   45:
x^2 - 4x - 45 = 4x + 45 - 4x -
   45
We'll eliminate like terms:
x^2 - 4x
   - 45 = 0
We'll pply the quadratic
   formula:
x1 = [4+sqrt(16 + 180)]/2
x1 =
   (4+14)/2
x1 = 9
x2 =
   (4-14)/2
x2 = -5
Since the length of
   the side of the square cannot be negative, we'll reject the second root x2 =
   -5.
The length of the side of the square is x =
   9.
 
No comments:
Post a Comment