Find the intercepts of the function y= x^2 -7x -8 = 0

Given the function y= x^2 - 7x
-8

We need to find the
intercepts.

First we will determine the
x-intercept.

The x-intercept is the point where the fnction meets
the x-axis.

Then the values of y will be
0.

==> x^2 - 7x -8 =
0

==> (x-8)(x+1) = 0

==>
x1 = 8

==> x2= -1

Then we have
two x-intercepts: (8, 0) and (-1, 0)

Now we will determine the
y-intercept.

The y-intercept is the point where the function meets
the y-axis, then the value of x is 0.

==> y= 0 - 0 -8 =
-8

Then the y-intercept is the point (0,
-8)

Then the intercepts
are:

x-intercepts are (8, 0) and
(-1,0)

y-intercept is ( 0,
-8)