tanx = 1/7. To find tan2x
.
We express tan2x , in terms of tanx and , then
substitute the given value of x to get tan2x.
We know that
tan(a+b) = (tanA +tanB)/{1-tanA*tanB}
Put A = B=
x.
Then tan2x = tan(x+x) =
(tanx+tanx)/(1-tanx*tanx)
Therefore tan2x =
2tanx/{1-(tanx)^2}..(1)
Now we substitute tanx = 1/7 in
eq(1):
tan2x =
2(1/7)/{1-(1/7)^2}
Multiply both numerator and denominator
by 49:
tan2x =
2*7/{49-1}
tan2x = 14/48
tan2x
= 7/24.
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