Thursday, September 29, 2011

Find the values of m for -3 + sqrt(m+59) = m.

First, we'll impose the condition of existence of the
square root.


m  +59
>=0


m >= -59


The
interval of admissible values of m are [-59 ;
+infinite)


Now, we'll solve the
equation:


-3 + sqrt(m+59) =
m


sqrt(m+59) = m + 3


We'll
raise to square both sides:


m + 59 =
(m+3)^2


m + 59 = m^2 + 6m +
9


We'll move all terms to the right side and we'll use the
symmetric property:


 m^2 + 6m + 9 - m - 59 =
0


We'll combine like
terms:


m^2 + 5m - 50 = 0


We'll
apply the quadratic formula:


m1 = [-5+sqrt(25 +
200)]/2


m1 =
(-5+15)/2


m1 =
5


m2 =
(-5-15)/2


m2 =
-10


Since both values are in the interval of
admissible values, they are accepted.

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