We'll start by imposing constraints of existence of the
square root.
x^2 + 2 >
0
Since te value of x^2 is always positive, no matter the
value of x is, the expression x^2 + 2 > 0.
Now,
we'll square raise both sides to get rid of the square
root.:
[sqrt(x^2 + 2)]^2 =
(x+3)^2
We'll expand the square from the right
side:
x^2 + 2 = x^2 + 6x +
9
We'll subtract x^2 + 6x + 9 and we'll eliminate like
terms:
-6x - 9 + 2 = 0
-6x - 7
= 0
We'll add 7 both
sides:
-6x = 7
We'll divide by
-6:
x = -7/6
x =
-1.1(6)
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