We consider the ski lift to be in a vertical plane and
the corresponding geometrical figure is as below:
Let us
draw a right angled triangle ABC representing the data.
AB
makes an angle of 15 degree with BC .
Let AB = 560 m
representing the ski lift which is inclined at an angle of 15 degree to the horizontal
plane.
BC is a a horizontal line from the bottom of the ski
lift.
Angle B= 15 degree.
A is
the top point of the ski lift.
C is the foot of
perpendicular from A on horizontal line BC.
Now ABC is a
right angled triangle.
Therefore, by definition, sineB =
opposite side / hypotenuse
Therefore, sin B =
AC/AB
Therefore AC =
AB*sinB
Therefore AC = (560 m )sine15 = 144.9387
m nearly.
Therefore the heit of the ski lift = AC =
144.9387 m , or 145 m.
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