We'll take the denominator of the first ratio and we'll multiply
1 by x:
1+1/x = (x+1)/x
We'll multiply
the numerator x of the first ratio by the inversed
denominator:
x*x/(x+1) =
x^2/(x+1) (1)
We'll re-write the second
ratio:
(1/x)/ (x + 1) = 1/x(x+1)
(2)
We'll add (1) + (2)
x^2/(x+1) +
1/x(x+1)
We'll multiply by x the first
ratio:
(x^3 + 1)/x(x+1)
We'll re-write
the sum of cubes:
x^3 + 1 = (x+1)(x^2 - x +
1)
(x^3 + 1)/x(x+1) = (x+1)(x^2 - x +
1)/x(x+1)
We'll simplify:
(x+1)(x^2 - x
+ 1)/x(x+1) = (x^2 - x + 1)/x
(x^2 - x + 1)/x = x^2/x - x/x +
1/x
(x^2 - x + 1)/x = x - 1 +
1/x
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