What are a and b if (a+2)/3+(b-1)/i-(a-1)*i^-1-(b+1)*2^-1 ?

It is not possible to find the values of a and b from the
expression you have provided. I have solved what I think would have been the equation: (a+2)/3 +
(b-1)/i = (a-1)*i^-1 - (b+1)*2^-1

(a+2)/3+(b-1)/i = (a-1)*i^-1 -
(b+1)*2^-1

=> (a+2)/3 + (b-1)/i = (a-1)/i -
(b+1)/2

=> [i(a+2) + 3(b - 1)]/3i = [2(a - 1) - i(b +
1)]/2i

=> [2i(a+2) + 6(b - 1)] = [6(a - 1) - 3i(b +
1)]

=> [2ai + 4i + 6b - 6] = [6a - 6 - 3bi -
3i]

equate the real and complex
coefficients

=> 2a + 4 = -3b - 3 and 6b - 6 = 6a -
6

6b - 6 = 6a - 6

=> a =
b

substitute a for b in 2a + 4 = -3b -
3

=> 2b + 4 = -3b - 3

=>
5b = -7

=> b = -7/5

a = b =
-7/5

The required values of a and b are a = -7/5 and b
= -7/5