sina+cosa = 1
To find tan 2a
.
We put cosa = sqrt(1-sin^2a) in the given
equation:
sina +sqrt(1-sin^2a) =
1
sqrt(1-sin^2a) =
1-sina.
Square both
sides:
1-sin^2a = 1 -2sina
+sin^2a
0 = -2sina +
2sin^2a
2sina(sina -1) =
0
sina = 0. Or sina = 1.
For
sina = 0 , we get:a = 0. , or a = pi.
For sina = 1, a = 90
degree.
Therefore , when a = 0 or pi, tan2a =
0
When a = pi/2 or 90 degree, tan2a = tan pi =
0
So tan2a = 0.
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