Sunday, January 10, 2016

What was the initial velocity of a body of mass 10 kg if it sticks to a a stationary body of mass 5 kg and the two move together at 4 m/s.

When two masses collide and stick to each other it is a
perfectly inelastic collision. Here the total momentum is not conserved, but the total
energy is conserved.


The kinetic energy is given by
0.5*m*v^2


Initially we have the mass of 10 kg moving. Let
its velocity be V.


Therefore its kinetic energy is 0.5*10*
V^2


The kinetic energy of the mass of 5 kg is
0.


Total kinetic energy in the system is 0.5*10*
V^2


After the collision , the two masses move at 4 m/s. The
kinetic energy in the system is .5* 15* 4^2


Equate .5* 15*
4^2 to 0.5*10* V^2


=> .5* 15* 4^2 = 0.5*10*
V^2


=> 15* 16 =
10*V^2


=> V^2 = 15*16/10 =
24


=> V = sqrt
24


Therefore the velocity of the 10 kg mass
initially was sqrt 24 m/s.

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