Find the surface area of a hexagonal prism with height of 12 cm and side length of 9 cm. Its geometry and i dont remember how to do it. Please...

The surface area is the perimeter of the base multiplied by the
height added to twice of the area of the base

SA = P*h +
2B

We'll calculate the perimeter of the
base:

p = 6*l, where l = 9 cm

P =
6*9

P = 54 cm

We'll multiply the
perimeter by the height:

P*h = 54 cm*12 cm = 648
cm^2

Now, we'll calculate the area of the
base:

B = 3*l^2*sqrt3/2

l = 9
cm

B = 3*81*sqrt3/2

B =
121.5*sqrt3

2B= 2*121.5*sqrt3

2B =
243*sqrt3

Now, we'll gather all the results and we'll compute the
surface area of the hexagonal prism:

SA = 648 +
243*sqrt3

SA = 1068.39
cm^2