The question put is to express the 6sinxcosx as the function of
single sine of cosine function.
As it is, the the given finction
a single function with both sinx and cosx. f(x) = 6sinxcosx.
We can
rewrite the function as a function of sinx as below:
f(sinx) = 6
sinx(1-sin^2x)^(1/2), as cosx = (1-sin^2x).
We can write the
function purely as a function of K*sinX as below:
6sinxcosx = 3
(2sinxcosx) = 3sin(2x)
6 sinxcosx = 3sin(2x) , as sin2x= sin(x+x) =
sinxcosx+cosxsinx = 2sinxcosx.
We can write 6sinxcosx = sin(2x) =
cos(90-2x)
We cane write the 6sinxcosx =
6cosx*(1-cos2^)^(1/2).
No comments:
Post a Comment