What are numbers whose sum is 4 and the product is -96.

Let a and b be the number such that their sum is 4 and
their product is -96.

Then we will
write:

a + b = 4
...............(1)

a*b = -96
.............(2)

Now we have a system of two equations and
two variables.

We will use the substitution method to
solve.

We will wrtie (1).

a +
b = 4

==> a = 4 - b

Now
we will substitute in (2).

a*b =
-96

==> ( 4-b)*b =
-96

==> 4b - b^2 =
-96

==> b^2 - 4b - 96 =
0

Now we will
factor.

==> ( b - 12) ( b + 8) =
0

==> b1 = 12  ==> a1 = 4-12 =
-8

==> b2= -8 ==> a2= 4-(-8) ==
12

Then, the numbers are 12 and
-8.