Monday, March 19, 2012

Fill in the squares 16x^4/36 - _ +36x^2/16= 81y^6 + 180y^3*x^5+_=

To complete the given squares, we'll have to work
according to the formula:


(a+b)^2 = a^2 + 2ab +
b^2


(a-b)^2 = a^2 - 2ab +
b^2


We'll analyze the
expression:


81y^6 +
180y^3*x^5+_=


We'll identify a^2 = 81y^6 => a = sqrt
81y^6


a = 9y^3


To calculate b,
we'll consider the second term of the square:


180y^3*x^5 =
2*a*b


180y^3*x^5 =
2*9y^3*b


We'll use the symmetric property and we'll divide
by -18y^3:


b =
180y^3*x^5/18y^3


b =
10x^5


Now, we'll complete the square by adding the amount
b^2.


b^2 = ( 10x^5)^2


b^2 =
100x^10


(a+b)^2 = (9y^3 +
10x^5)^2


The missing term in the quadratic expression is
100x^10:


(9y^3 + 10x^5)^2 = 81y^6 +
180y^3*x^5+100x^10


2) We notice that the
missing term is -2ab.


We'll identify a^2 = 16x^4/36
=> a = sqrt 16x^4/36 => a = 4x^2/6


16x^4/36 -
2*4x^2/6*b + 36x^2/16 = 0


To calculate 2ab, we'll consider
the 3rd term of the square:


36x^2/16 =
b^2


b = sqrt 36x^2/16


b =
-6x/4


2*4x^2/6*(-6x/4) =
-2x^3


The missing term in the quadratic expression is -2x^3
and the completed square will be:


(4x^2/6 -
6x/4)^2 = 16x^4/36-2x^3+36x^2/16

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