fog(10) is the same as writing f(g(10)). Now we are given that
f(x) = log x and g(x) = x^2.
To find fog(10)= f(g(10)), we first
find g(10).
This is equal to 10^2.
Now
substitute g(10) = 10^2 as the x value in f(x).
We get f(g(10)) = f(
10^2) = log (10^2)
Now we use the relation that log (a^b) = b* log
a.
log (10^2) = 2 * log 10.
Now if the
base of the log is 10 log 10= 1.
Else we can write the general
result for fog(10) as 2 log 10.
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