Solve the equation: 5x^2 + 13 x +8 =0

The quadratic equation 5x^2 + 13x  +8 =0 has to be
solved.

The solution of quadratic equation ax^2 + bx + c =
0 is given by the formula `(-b+-sqrt(b^2 - 4ac))/(2a)`

For
5x^2 + 13x  +8 =0, a = 5, b = 13 and c = 8. Substituting these values in the formula for
the roots gives:

`(-13+-sqrt(13^2 -
4*5*8))/(2*5)`

= `(-13+-sqrt(169 -
160))/(2*5)`

=
`(-13+-sqrt(9))/(2*5)`

= `(-13 - 3)/10` and `(-13 +
3)/10`

= -1.6 and -1

The roots
of the equation are -1 and -1.6