For any system of logarithms we can use the relation: log
            (a) b = log(x) a / log(x) b where x can be any positive number to be use as the
            base.
Now using x= 2,
log (8)
            256 = log(2) 256 / log(2) 8.
But we know that log(2) 8
            =3
Also log (2) 256 = 8
So
            log(2) 256 / log(2) 8 = 8/3
Or log(2) x =
            8/3
Raising both sides to the power 2, we
            get
x =
            2^(8/3)
Therefore x =
            2^(8/3)
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