Given that the sum of the integers a and b is
57.
==> a + b= 57
............(1)
We are given that b is 3 less than double
a.
==> Then we will rewrite :
b=
2a - 3 ...............(2)
Now, using the substitution method, we
will substitute (2) into (1).
==> a + (2a-3) =
57
==> 3a - 3 = 57
We will add 3
to both sides.
==> 3a =
60
==> a = 60/3 = 20
==>
b= 2a-3 = 2*20 -3 = 40-3 = 37
==> Then the
numbers are : a = 20 and b = 37.
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