In which quadrant does the line 5y-3x+1 = 0 meets the line 2y-4x +7 = 0?

To determine the quadrant we will need to find the intersection
point between the lines , then we determine the location.

==>
5y-3x + 1 = 0 ==> y= (3x-1)/5 ............(1)

==>
2y-4x + 7 = 0==> y= (4x-7)/2 ............(2)

Now we will find
the intersection point.

==> (3x-1)/5 =
(4x-7)/2

Cross multiply.

==>
2(3x-1) = 5(4x-7)

==> 6x -2 = 20x -
35

==> 14x = 33

==> x =
33/14= 2.36

==> y= (3x-1)/5 = (3*2.36 -1 )/5 =
1.21.

Then the point of intersection is ( 2.36,
1.21)

Then, the point if located in the first
quadrant.