Decopose in simply fractions. 2/2x(6x+4)

We'll have to get 2 irreducible fractions because of the 2
factors from denominator.

2/2x(6x+4) = 1/x(6x+4)

The final ratio
1/x(6x+4) is the result of addition or subtraction of 2 elementary fractions, as it
follows:

1/x(6x+4) = A/x + B/(6x+4)
(1)

We'll multiply by x(6x+4) both
sides:

1 = A(6x+4) + Bx

We'll remove
the brackets:

1 = 6Ax + 4A + Bx

We'll
factorize by x to the right side:

1 = x(6A+B) +
4A

Comparing both sides, we'll
get:

6A+B = 0

4A = 1 => A =
1/4

6/4 + B = 0

B =
-3/2

We'll substitute A and B into the expression (1) and we'll get
the algebraic sum of 2 elementary
fractions:

2/2x(6x+4) = 1/x(6x+4) = 1/4x - 3/2(6x +
4)