If x= 2. Find x^2/3 ( x^120/ x^110) * x^-7 ?

Given x = 2.

Let E (x) =
 x^2/3 ( x^120/ x^110) * x^-7

Then, we need to calculate
E(2).

First, let us simplify the
expression.

x^2/3 ( x^120 / x^110) *
x^-7

Let us simplify between the
brackets.

( x^120/ x^110)

We
know that x^a/ x^b = x^(a-b).

==> x^120/ x^110 =
x^(120-110)= x^10

==> E(x) = (x^2/3) ( x^10) *
x^-7

Now we know that x^a* x^b =x^
(a+b).

==> E(x) = x^ ( 2/3 + 10 +
-7)

                = x^ (2/3 +
3)

                 =
x^(11/3).

==> E(x) = x^
11/3

Now let us substitute with x=
2.

==> E(2) = 2^11/3 = 12.7 (
approx.)

Then E (x) = 12.7 
when x = 2.