Label the following line equations as parallel or coinciding: 3/5x-7/5y=1x-7/3y=5/3

3/5x -7/5y =
1......(1)

x-7/3y =
5/3..........(2)

 From the 2nd equation we get x = 5/3
-7/3y = (5y-7)/3y.

We substitute  x =  (5y-7)/3y in
(1).

3*3y/5(5y-7) -7/5y = 1. Multiply by
5y(5y-7).

9y*y - 7(5y-7)  =
5y(5y-7)

9y^2 -35y+49 = 25y^2
-35y

49 = 25y^2. So y^2
=49/25.

y = 7/5 or y =
-7/5.

Substituting in (2)   y values , we get: x =
5/3+7/3y.

So x= 5/3 +7/3(7/5) = 5/3 +5/3 =
10/3.

x = 5/3 +7/3(-7/5) = 5/3 -5/3 =
0.

So (x ,y) = (0 , -7/5) , Or (x,y) = (10/3 ,
7/5)