Thursday, April 7, 2011

Determine the neutral element of the law of composition x*y = 3xy + 6(x+y) + 10

To determine the neutral element we'll write it's
property:


x*e = e*x = x


Now,
we'll apply the law of composition for


 x*e = 3xe + 6(x+e)
+ 10


But x*e = x


3xe + 6(x+e)
+ 10 = x


We'll remove the
brackets:


 3xe + 6x + 6e + 10 =
x


We'll isolate all the elements that contain e to the left
side:


3xe + 6e = x - 6x -
10


We'll factorize by 3e to the left side and we'll combine
like terms to the right side:


3e(x + 2) = -5x -
10


We'll factorize by -5 to the right
side:


3e(x + 2) =
-5(x+2)


We'll divide by (x+2) and we'll
get:


3e = -5


The
neutral element is e = -5/3.

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