ABC is a right angle triangle. AB = 10 A = 27 degree. Find BC if AC is the hypotenuse.

We are given that ABC is a right triangle. AB is equal to
10 and the Angle A is 27 degree. Also, AC is the
hypotenuse.

Now cos A = adjacent side /
hypotenuse

=> cos A = AB/
AC

=> cos 27 = 10 /
AC

=> 0.891 = 10 /
AC

=> AC = 10/
.891

=> AB = 11.22 (
approximately)

For
BC we can use the Pythagorean Theorem. We have

AC^2 = AB^2
+ BC^2

=> 11.22^2 = (10)^2 +
BC^2

=> BC^2 = 11.22^2 -
10^2

=> BC^2 = 125.96 -
100

=> BC^2 =
25.96

=> BC = 5.09 (
approximately)

Therefore the
required value of BC is 5.09