The lines x+y = 20 and 3x-2y= 6 must inersect as their
slopes are obviously looking different.
Slope of x+y = 20
or y = 20-x (which is in y = mx+c , m is slope ) is
-1.
Slope of of 3x-2y = 6 or -2y = -3x+6 , or y
=(3/2)x- 6/2 , is
3/2.
Intersection of the lines are the solution of the
equations:
x+y =
20..............(1)
3x-2y =
6..................(2)
Add 2*eq(1) and eq(2 ) . Then y gets
eliminated:
2x+3x = 2*20+6 =
46
5x=46
x = 46/5=
9.2.
Eq(3)*3 - Eq(2) eliminates
x:
3y- (-2y) = 3*20-6 = 56
5y
= 56
y = 54/5 = 10.4
Therefore
(x,y) = (9.2 , 10.4) are the coordinates of the point of intersection of the 2
lines.
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