tana = 3/4 tan b =
2/7
We know that:
tan(a-b) =
(tan a - tanb)/(1+ tana*tanb)
Let us
substitute:
tan(a-b) = (3/4 - 2/7) / [1+
(3/4)*(2/7)]
= (21-8)/28 / (1+
6/28)
= 13/28 /
(34/28)
=
13/34
==> tan(a-b) =
13/34
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