Let Pl = volume drained by one large pipe in one
hour
Let Ps = volume drained by one small pipe in one
hour
Let t = time
V - 9P*8 = 0
V-6*p*(16) = 0
+(-V+6p*16 =
0) V = 6*p*16
-9Pl*8+6ps*16 =
0
9P*8 = 6p*16 V-3(P)(t)-5(p)(t) =
0
P = 1.33p -------------->
6p*16-3(1.33p)(t)-5(p)(t) =
0
96p-4pt-5pt =
0
96p =
9pt
t =
(96p)/(9p)
t = 10.667
hrs = 10 hrs 40 min
==> t= 10 hrs 40
min
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