At what point does the line 2y-3x+5 = 0 meets the line 3y-4x-8 = 0 ?

Given the lines:

2y-3x + 5 =
0...........(1)

3y-4x -8=
0..............(2)

Both line meets at a point, This point is the
solution to the system.

We will use the elimination method to find
the points.

We will multiply (1) by 3 and (2) by
-2

3*(1) ==> 6y -9x +15 =
0

-2*(2)==> -6y +8x +16 = 0

Now
we will add both equations.

==> -x + 31 =
0

==> -x = -31

==> x =
31

==> y= (3x-5)/2 = 3*31-5 /2 = 93-5 /2 = 88/2 =
44

Then the lines meets at the point (31,
44)