What are the solutions of equation 2x^2-8x-192=0?

First, simplify the equation by doing common factor.  So
the equation becomes 2(x^2 - 4x - 96) = 0.

To get the
solutions of the equation, we just have to factor (x^2 - 4x - 96) =
0,

(x - 12)(x + 8) =
0

Equating the two factors to
0,

x - 12 = 0, x = 12

x + 8 =
0, x = -8

Be sure to check the solutions by substituting -8
& 12 to the original equation.