50/ (2t+4) = (2t+4) / 2
First
we will cross multiply.
==> (2t+4)*(2t+4) =
2*50
==> (2t+4)^2 =
100.
Now we will take the root of both
sides.
==> (2t+4) =
+-10.
Then, we have two
cases.
Let us solve each
case.
==> (2t+4)= 10 ==> 2t = 6 ==>
t1= 3
==> (2t+4) = -10 ==> 2t = -14
==> t2= -7.
Then there are two values for
t.
t= { -7,
3}.
To check the
answer, we will substitute with t1 and
t2.
If t= -7 ==> 50/(2*-7 + 4) = (2*-7+4)/
2
==> 50/ (-10) =
-10/2
==> -5 = -5
If t=
3 ==> 50/(2*3+4) = (2*3+4)/2
==> 50/ (10) =
(10)/ 2
==> 5 = 5.
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