Solve for x if 3x^3 + 27x^2 = 30x.

Given the equality: 3x^3 + 27x^2 =
30x.

We need to solve for x value that satisfies the
equality.

First, let us simplify the
equality.

We will subtract 30x from both
sides.

==> 3x^3 + 27x^2 - 30x =
0

Now we notice that (3x) is a common factor for all
terms.

Then, we will factor
(3x).

==> 3x*(x^2 + 9x - 10 ) =
0

Now we will factor between the
brackets.

==> 3x ( x+10) ( x-1) =
0

Then we have 3 possible values for x that
satisfies the
equality.

==> x1=
0

==> x2=
-10

==> x3=
1

==> x = { 0, 1, -10
}